提问网友:杨成睿
提问日期:2024-06-17 22:33:32
1.当hc-bhc≥lae时,取直锚=Max(lae,0.5hc+5d)
当hc-bhc<lae时,取弯锚=(hc-bhc)+15d
2.当hc-bhc≥lae时,取直锚=lae
当hc-bhc<lae时,取弯锚=Max(hc-c,0.4lae)+15d
解答网友:星辰大海
黄金专家
1.当hc-bhc≥lae时,取直锚=Max(lae,0.5hc+5d)
当hc-bhc<lae时,取弯锚=(hc-bhc)+15d
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